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Or the comparison against a signed char is always true, because the literal 0xaa is treated as an unsigned int, to which the signed char is casted during comparison. 0xaa is above the positive values of a signed char and negative signed char values result in values larger than 0xaa when casted to unsigned int. Signed-off-by: Sven Wegener <sven.wegener@stealer.net> |
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imagebuilder | ||
linux | ||
llvm-bpf | ||
sdk | ||
toolchain | ||
Config.in | ||
Makefile |