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802.11n rx performance fix when used different clock rates (i.e. 100MHz vs 200MHz)
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@ -178,6 +178,7 @@ reg sync_short_reset;
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reg sync_long_reset;
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wire sync_short_enable = state == S_SYNC_SHORT;
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reg sync_long_enable;
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wire [15:0] num_ofdm_symbol;
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reg equalizer_reset;
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reg equalizer_enable;
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@ -325,7 +326,8 @@ sync_long sync_long_inst (
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.state(sync_long_state),
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.sample_out(sync_long_out),
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.sample_out_strobe(sync_long_out_strobe)
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.sample_out_strobe(sync_long_out_strobe),
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.num_ofdm_symbol(num_ofdm_symbol)
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);
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equalizer equalizer_inst (
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@ -781,7 +783,16 @@ always @(posedge clock) begin
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state <= S_HT_SIG_ERROR;
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end else begin
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sync_long_out_count <= 0;
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// When decoding 80211n packets, a lower clock running platform (i.e. zedboard @ 100MHz) will spend more than 4usec to decode an entire OFDM symbol.
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// This creates misalignment between the control state and the actual decoding process since a feedback mechanism is not applied.
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// By the time the 1st OFDM DATA symbol is being decoded, the control is in HT-LTS state and the equalizer module mistakenly calculates the channel gain.
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// A quick fix for this is to bypass the HT-STS symbol to re-establish the alignment. Afterall, HT-STS is not used in this module.
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if (num_ofdm_symbol == 5) begin
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state <= S_HT_STS;
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end else begin
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ht_next <= 1;
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state <= S_HT_LTS;
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end
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end
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end
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@ -17,6 +17,7 @@ module sync_long (
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output reg [31:0] sample_out,
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output reg sample_out_strobe,
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output reg [15:0] num_ofdm_symbol,
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output reg [2:0] state
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);
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@ -237,7 +238,6 @@ xfft_v9 dft_inst (
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);
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reg [15:0] num_sample;
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reg [15:0] num_ofdm_symbol;
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integer i;
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integer j;
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